Sum of series 1 + 1/2 + 1/3 + 1/4 + ....N

C Program to print sum of series 1 + 1/2 + 1/3 + 1/4 + ....N for the given value of N.

For example, if N=5, output will be sum of 1 + 1/2 + 1/3 + 1/4 + 1/5, i.e. 2.28 

#include<stdio.h>
int main()
{
  int i, N;
  float sum=0;
  printf("Enter N:");
  scanf("%d", &N);
  if(N<1){
  printf("Enter value of N > 0.");
  exit(1);
  }
  for(i=1; i<=N; i++)
  {
   if(i==1)
   {
  sum=1;
  printf("Series = 1");
   }
   else
   {
     sum = sum + (float)1/i;
     printf(" + 1/%d", i);
   }
  }
  printf("\nSum of the series = %0.2f", sum);
  return 0; 
}

Output of program

Enter N:5
Series = 1 + 1/2 + 1/3 + 1/4 + 1/5
Sum of the series = 2.28

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