Dynamic memory allocation using malloc

malloc() - Dynamic memory allocation function

The process of allocating memory at program run time is known as dynamic memory allocation. Following program will dynamically allot space as per user requirement.

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int i, n;
    int *myspace;

    printf("Enter total numbers to be stored: ");
    scanf("%d", &n);
    
    /*Following statement will allot n blocks of int in memory.
      malloc returns a void pointer; then it is type-casted to (int*).
      myspace points to the first block of the newly allocated space.
    */
    myspace = (int*) malloc(n*sizeof(int)); 
    
    //It returns NULL pointer, if fails to allocate enough space.
    if(myspace == NULL) 
    {
        printf("Error!!! Space problem..");
        exit(0);
    }
    //Logic to store numbers to dynamically allocated space
    for(i=0; i<n; i++)
    {
       printf("Enter number %d:",i+1);
       scanf("%d", myspace+i); 
    }
    //Logic to print numbers from dynamically allocated space
    printf("\n%d numbers stored in dynamically allotted space:\n", n);
    for(i=0; i<n; i++) 
    {
    printf("%d ", *(myspace+i));
    }
    return 0;
}


Output of program

Enter total numbers to be stored: 5
Enter number 1:2
Enter number 2:4
Enter number 3:6
Enter number 4:8
Enter number 5:10

5 numbers stored in dynamically allotted space:
2 4 6 8 10