Predict C Program Output-2 Answer

Program-1

#include<stdio.h>

int main()

{

  printf("Hello");

  printf("\rIndia");

  return 0;

}

Output: India

Justification: \r is linefeed character.

Program-2

#include<stdio.h>

int main()

{

  int number = - -5;

  printf("number = %d",number);

  return 0;

}

Output: number = 5

Justification: Here, unary minus sign used twice. Hence minus * minus becomes plus.

Program-3

#include<stdio.h>

#define float char

int main()

{

  float num=65;

  printf("Size of(num) = %d",sizeof(num));

  return 0;

}

Output: Size of(num) = 1

Justification: #define replaces the string float by char, hence num becomes char type variable.

Program-4

#include<stdio.h>

enum colors {RED, BLUE, GREEN};

int main()

{

  printf("%d, %d, %d",BLUE, RED, GREEN);

  return 0;

}

Output: 1, 0, 2

Justification: By default, enum assigns numbers starting from 0 to its variables.

Program-5

#include<stdio.h>

void display(void);

int main()

{

  int i=1;

  for(i=0; i<=5; i++)

  {

     printf("%d",i);

     if (i>2)

        goto ABC;

  }

}

display()

{

  ABC:

  printf("Hello World");

}

Output: Compile time error.

Justification: goto and Label(ABC) is not defined in same function.